GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The figure above shows a rectangular play area in which one child sta
[#permalink]
28 May 2021, 04:52
28 May 2021, 04:52
Expert Reply
00:00
Question Stats:
83% (01:35) correct
16% (02:50) wrong based on 6 sessions
Hide Show timer Statistics
Attachment:
shot71.jpg [ 11.75 KiB | Viewed 1573 times ]
The figure above shows a rectangular play area in which one child stands at B while another child runs back and forth along the entire side AD. If the running child is in a position randomly located along side AD at a given time, what is the probability that the two children are at most 50 feet apart at that time?
A. 1/5
B. 2/5
C. 3/5
D. 4/5
E. 1
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: The figure above shows a rectangular play area in which one child sta
[#permalink]
29 May 2021, 01:42
29 May 2021, 01:42
Carcass wrote:
Attachment:
The attachment shot71.jpg is no longer available
The figure above shows a rectangular play area in which one child stands at B while another child runs back and forth along the entire side AD. If the running child is in a position randomly located along side AD at a given time, what is the probability that the two children are at most 50 feet apart at that time?
A. 1/5
B. 2/5
C. 3/5
D. 4/5
E. 1
Since, both of them have to be 50 ft apart, let us join BD' such that BD' = 50
Apply Pythagoras theorem in triangle ABD':
\(50^2 = 30^2 + (AD')^2\)
\(AD' = 40\)
Now, probability that the two children are at most 50 feet apart = \(\frac{Area (△ABD')}{ Area (△ABD)} = \frac{(30)(40)}{(30)(50)} = \frac{40}{50} = \frac{4}{5}\)
Hence, option D
Attachments
The figure above shows a rectangular play area.png [ 7.38 KiB | Viewed 1554 times ]
gmatclubot
Re: The figure above shows a rectangular play area in which one child sta [#permalink]
29 May 2021, 01:42
Moderators:
