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The figure shown above is a right circular cylinder. The circumferenc
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20 May 2021, 09:36
20 May 2021, 09:36
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Question Stats:
62% (01:50) correct
37% (02:24) wrong based on 8 sessions
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GRE The figure shown above.jpg [ 17.54 KiB | Viewed 2465 times ]
The figure shown above is a right circular cylinder. The circumference of each circular base is 20, the length of ๐ด๐ท is 14, and ๐ด๐ต and ๐ถ๐ท are diameters of each base respectively. If the cylinder is cut along ๐ด๐ท, opened, and flattened, what is the length of ๐ด๐ถ to the nearest tenth?
Show: :: OA
17.2
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Re: The figure shown above is a right circular cylinder. The circumferenc
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21 May 2021, 22:00
21 May 2021, 22:00
Carcass wrote:
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The attachment GRE The figure shown above.jpg is no longer available
The figure shown above is a right circular cylinder. The circumference of each circular base is 20, the length of ๐ด๐ท is 14, and ๐ด๐ต and ๐ถ๐ท are diameters of each base respectively. If the cylinder is cut along ๐ด๐ท, opened, and flattened, what is the length of ๐ด๐ถ to the nearest tenth?
Show: :: OA
17.2
When the cylinder is cut open, we will get a rectangle with height = breadth = 14 and circumference of base = length = 20 (as shown in the figure below)
Join AC;
\(AC^2 = AD^2 + DC^2\)
\(AC = \sqrt{14^2 + 10^2} = \sqrt{296}\)
\(AC = 17.2\)
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The figure shown above is a right circular cylinder.png [ 7.14 KiB | Viewed 2402 times ]
gmatclubot
Re: The figure shown above is a right circular cylinder. The circumferenc [#permalink]
21 May 2021, 22:00
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