Helo,
there is a small doubt i'm having in this explanation, how can the area of a triangle is the greatest when it is the right-angled triangle.
can someone give me diagramatic explanation.
and why we need to consider 4 and 5 as the perpendicular sides why not hypothenuse.

what is the proper algorithm here? Both the provided solutions are quite intuitive

In Qt A, we are asked to find the greatest possible area.

Now consider a case where 5 is the hypotenuse. So the sides will be 3 & 4. Even if you consider that case, the area of the triangle will be 6.

As we are told to go for the maximum area, we should look out for all the reasons to get Qt A either equal to or greater than Qt B so that we can arrive at the answer.

So in this case, how much more we try, we will end up getting 10 as the highest area. You can consider any other triangle. But area of the right-angled one is always the greatest. Hope this helps!


R

Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.