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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
The length of a certain rectangle is 4 inches longer than its width.
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28 Jul 2021, 02:51
28 Jul 2021, 02:51
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The length of a certain rectangle is 4 inches longer than its width. If the area of the rectangle is 221 square inches, then the length of the rectangle’s diagonal, in inches, is
(A) between 19 and 20
(B) between 20 and 21
(C) between 21 and 22
(D) between 22 and 23
(E) between 23 and 24
(A) between 19 and 20
(B) between 20 and 21
(C) between 21 and 22
(D) between 22 and 23
(E) between 23 and 24
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
The length of a certain rectangle is 4 inches longer than its width.
[#permalink]
28 Jul 2021, 11:29
28 Jul 2021, 11:29
GeminiHeat wrote:
The length of a certain rectangle is 4 inches longer than its width. If the area of the rectangle is 221 square inches, then the length of the rectangle’s diagonal, in inches, is
(A) between 19 and 20
(B) between 20 and 21
(C) between 21 and 22
(D) between 22 and 23
(E) between 23 and 24
(A) between 19 and 20
(B) between 20 and 21
(C) between 21 and 22
(D) between 22 and 23
(E) between 23 and 24
legth=x, width=x-4
area=x(x-4)=221, find Sqroot [x^2 + (x^2 - 8x +16)] ?
x^2 - 4x =221 and 2x^2 - 8x = 221*2 = 442. Diagonal's length is Sqroot [442+16] = Sqroot [458] is between 21 and 22. Answer is C.
gmatclubot
The length of a certain rectangle is 4 inches longer than its width. [#permalink]
28 Jul 2021, 11:29
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