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The sum of A and B's age is 43 years. In 11 years, A's age will be 7/6
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15 Apr 2021, 03:47
15 Apr 2021, 03:47
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The sum of A and B's age is 43 years. In 11 years, A's age will be 7/6 times B's age. What is B's present age?
A. 24 years
B. 22 years
C. 20 years
D. 19 years
E. 18 years
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 24 years
B. 22 years
C. 20 years
D. 19 years
E. 18 years
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: The sum of A and B's age is 43 years. In 11 years, A's age will be 7/6
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15 Apr 2021, 06:07
15 Apr 2021, 06:07
1
Carcass wrote:
The sum of A and B's age is 43 years. In 11 years, A's age will be 7/6 times B's age. What is B's present age?
A. 24 years
B. 22 years
C. 20 years
D. 19 years
E. 18 years
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 24 years
B. 22 years
C. 20 years
D. 19 years
E. 18 years
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
The sum of A and B's age is 43 years.
Let B = B's PRESENT age
So, 43 - B = A's PRESENT age
In 11 years....
B + 11 = B's age IN 11 YEARS
(43 - B) + 11 = A's age IN 11 YEARS
..., A's age will be 7/6 times B's age.
We can write: (43 - B) + 11 = (7/6)(B + 11)
Simplify the left side: 54 - B = (7/6)(B + 11)
To eliminate the fraction, multiply both sides of the equation by 6 to get: 6(54 - B) = (7)(B + 11)
Expand: 324 - 6B = 7B + 77
Add 6B to both sides of the equation: 324 = 13B + 77
Subtract 77 from both sides: 247 = 13B
Solve: B = 247/13 = 19
Answer: D
gmatclubot
Re: The sum of A and B's age is 43 years. In 11 years, A's age will be 7/6 [#permalink]
15 Apr 2021, 06:07
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