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The sum of three consecutive positive integers is always divisible by
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16 May 2022, 04:12
16 May 2022, 04:12
Expert Reply
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Question Stats:
64% (00:30) correct
35% (00:17) wrong based on 14 sessions
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The sum of three consecutive positive integers is always divisible by
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6
Part of the project: Skill Builder Project for a Q170
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
The sum of three consecutive positive integers is always divisible by
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16 May 2022, 07:54
16 May 2022, 07:54
1
The correct answer choice is B: 3.
You can solve this problem by testing out potential values that fit the criteria.
A few examples of three consecutive positive numbers would be: 123, 234, 567, and 678.
Adding them together:
1+2+3 = 6
2+3+4 = 9
5+6+7 = 18
6+7+8 = 21
From these examples, we can see that the numbers are always divisible by 3. Notice that it's important to test some numbers that start with an odd number and some that start with an even number. If you only tested numbers that started with odd numbers, you might incorrectly choose answer choice A.
You can solve this problem by testing out potential values that fit the criteria.
A few examples of three consecutive positive numbers would be: 123, 234, 567, and 678.
Adding them together:
1+2+3 = 6
2+3+4 = 9
5+6+7 = 18
6+7+8 = 21
From these examples, we can see that the numbers are always divisible by 3. Notice that it's important to test some numbers that start with an odd number and some that start with an even number. If you only tested numbers that started with odd numbers, you might incorrectly choose answer choice A.
gmatclubot
The sum of three consecutive positive integers is always divisible by [#permalink]
16 May 2022, 07:54
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