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Towns A, B, C, and D are all in the same voting district. Towns A and
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30 May 2023, 00:40
30 May 2023, 00:40
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70% (02:33) correct
29% (02:25) wrong based on 27 sessions
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Towns A, B, C, and D are all in the same voting district. Towns A and B have 3,000 people each who support referendum R and the referendum has an average (arithmetic mean) of 3,500 supporters in towns B and D and an average of 5,000 supporters in Towns A and C.
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
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Quantity A |
Quantity B |
The average number of supporters of Referendum R in Towns C and D |
The average number of supporters of Referendum R in Towns B and C |
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
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Re: Towns A, B, C, and D are all in the same voting district. Towns A and
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02 Jun 2023, 04:45
02 Jun 2023, 04:45
1
Expert Reply
OE
This is an average question, so make an Average Pie any time the word average is used. Begin by figuring out how many supporters of the referendum are in each town. The question states that there is an average of 3,500 supporters in Towns B and D, so there is a total of 3,500 × 2 = 7,000 supporters in these towns. The question also states that Town B has 3,000 supporters, so the number of supporters in Town D is 7,000 − 3,000 = 4,000. Additionally, the question states that there is an average of 5,000 supporters in Towns A and C, so there is a total of 5,000 × 2 = 10,000 supporters in these towns.
It’s also stated that Town A has 3,000 supporters, so the number of supporters in Town C is 10,000 − 3,000 = 7,000. Now, compare the quantities. Quantity A is the average number of supporters for Towns C and D, and Quantity B is the average number of supporters for Towns B and C. Because both quantities use Town C, and both quantities ask for an average, those values cancel out and all that remains is to compare the number of supporters in Towns B and D. There are 3,000 supporters in Town B and 4,000 in Town D, so Quantity A is greater, and the correct answer is (A). Alternatively, solve for the average given in both quantities. However, the result is the same; the correct answer is (A).
This is an average question, so make an Average Pie any time the word average is used. Begin by figuring out how many supporters of the referendum are in each town. The question states that there is an average of 3,500 supporters in Towns B and D, so there is a total of 3,500 × 2 = 7,000 supporters in these towns. The question also states that Town B has 3,000 supporters, so the number of supporters in Town D is 7,000 − 3,000 = 4,000. Additionally, the question states that there is an average of 5,000 supporters in Towns A and C, so there is a total of 5,000 × 2 = 10,000 supporters in these towns.
It’s also stated that Town A has 3,000 supporters, so the number of supporters in Town C is 10,000 − 3,000 = 7,000. Now, compare the quantities. Quantity A is the average number of supporters for Towns C and D, and Quantity B is the average number of supporters for Towns B and C. Because both quantities use Town C, and both quantities ask for an average, those values cancel out and all that remains is to compare the number of supporters in Towns B and D. There are 3,000 supporters in Town B and 4,000 in Town D, so Quantity A is greater, and the correct answer is (A). Alternatively, solve for the average given in both quantities. However, the result is the same; the correct answer is (A).
gmatclubot
Re: Towns A, B, C, and D are all in the same voting district. Towns A and [#permalink]
02 Jun 2023, 04:45
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