Carcass wrote:
Train A left Centerville Station, heading toward Dale City Station, at 3: 00 p.m. Train B left Dale City Station, heading toward Centerville Station, at 3: 20 p.m. on the same day. The trains rode on straight tracks that were parallel to each other. If Train A traveled at a constant speed of 30 miles per hour and Train B traveled at a constant speed of 10 miles per hour, and the distance between the Centerville Station and Dale City Station is 90 miles, when did the trains pass each other?
A. 4: 45 p.m.
B. 5: 00 p.m.
C. 5: 20 p.m.
D. 5: 35 p.m.
E. 6: 00 p.m.
3:00pm - Train A (traveling 30 miles per hour) left Centerville Station, heading toward Dale City StationIf the train travels 30 miles EVERY HOUR, then it travels 10 miles every 20 minutes (since 20 minutes = 1/3 hours)
In other words, at 3:20pm, Train A has already traveled 10 miles.
So,
at 3:20, the trains are now 80 miles apart.
3:20pm - Train B (traveling 10 miles per hour) left Dale City Station heading toward Centerville StationAt this point (at 3:20pm), the trains are 80 miles apart.
Also,
every hour, Train A moves 30 miles toward train B, and Train B moves 10 miles towards train A. This means the gap between them is decreasing at a rate of 40 miles per hour.
At this rate, the 80-mile gap will be reduced to zero miles (i.e., the trains meet) in 2 hours.
So, the trains will meet at
3:20pm + 2 hours = 5:20pm
Answer: C