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If a fair six-sided die with faces numbered 1 through 6 is t
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18 Mar 2020, 10:02
18 Mar 2020, 10:02
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Question Stats:
74% (00:48) correct
25% (01:26) wrong based on 27 sessions
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If a fair six-sided die with faces numbered 1 through 6 is tossed 3 times, what is the probability of getting a 1 or a 2 on all three tosses?
Kudos for the right answer and explanation
Show: :: OA
\(\frac{1}{27}\)
Kudos for the right answer and explanation
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Re: If a fair six-sided die with faces numbered 1 through 6 is t
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20 Mar 2020, 06:34
20 Mar 2020, 06:34
Carcass wrote:
If a fair six-sided die with faces numbered 1 through 6 is tossed 3 times, what is the probability of getting a 1 or a 2 on all three tosses?
Kudos for the right answer and explanation
Show: :: OA
\(\frac{1}{27}\)
Kudos for the right answer and explanation
There are 6 possible outcomes when rolling a die: 1, 2, 3, 4, 5, 6
So, P(1 or 2) = 2/6 = 1/3
We want the probability of getting a 1 or a 2 on all three tosses
P(1 or a 2 on all three tosses) = P(1 or 2 on 1st toss AND 1 or 2 on 2nd toss AND 1 or 2 on 3rd toss)
= P(1 or 2 on 1st toss) x P(1 or 2 on 2nd toss) x P(1 or 2 on 3rd toss)
= 1/3 x 1/3 x 1/3
= 1/27
Answer: 1/27
Cheers,
Brent
Re: If a fair six-sided die with faces numbered 1 through 6 is t
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12 Jun 2020, 20:45
12 Jun 2020, 20:45
Probability of getting 1 OR 2 first time: 1/6 + 1/6 = 2/6 = 1/3
Probability of getting 1 OR 2 second time: 1/6 + 1/6 = 2/6 = 1/3
Probability of getting 1 OR 2 third time: 1/6 + 1/6 = 2/6 = 1/3
Probability of getting 1 OR 2 1st AND 2nd AND 3rd time: 1/3 * 1/3 * 1/3 = 1/27
Please correct me if I am wrong.
Probability of getting 1 OR 2 second time: 1/6 + 1/6 = 2/6 = 1/3
Probability of getting 1 OR 2 third time: 1/6 + 1/6 = 2/6 = 1/3
Probability of getting 1 OR 2 1st AND 2nd AND 3rd time: 1/3 * 1/3 * 1/3 = 1/27
Please correct me if I am wrong.
