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x and y are both integers

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Carcass
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x and y are both integers [#permalink] New post   30 Jan 2020, 10:41
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x and y are both integers


Quantity A
Quantity B
xy
6



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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Re: x and y are both integers [#permalink] New post   15 Feb 2020, 16:31
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pprakash786 wrote:
Can someone please explain this?


I believe this is a faulty question.

If x and y are both INTEGERS, and if x^y and y^x are both NEGATIVE, then that means integers x and y are both NEGATIVE.

The graphic tells us that -10 < y^x < -1
However, if x and y are both NEGATIVE INTEGERS, then y^x cannot be less than -1.

Cheers,
Brent
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Re: x and y are both integers [#permalink] New post   14 Feb 2020, 21:38
Can someone please explain this?
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Re: x and y are both integers [#permalink] New post   18 Aug 2023, 08:32
Can someone please explain this?
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Re: x and y are both integers [#permalink] New post   18 Aug 2023, 10:26
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OE


As soon as you see variables and Quant Comp, make your set-up.

Plugging In is tricky here until you realize that one number must be negative. The 6 in Quantity B is also a clue. Try x = 3 andy = -2. y to the x power will be -8 and x to the y power will be 1/9, so these numbers work. xy = -6 so cross off choices (A) and (C). No matter what you plug in, y must be negative and x must be odd. Therefore xy will always be negative and 6 will always be greater. The answer is choice (B).
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Re: x and y are both integers [#permalink] New post   06 Sep 2023, 17:11
I'm a little confused, because 1/9 is not between -1 and 0. I understand the logic behind the rest of the question, but not that part. Do you mind explaining a bit more?


Carcass wrote:
OE


As soon as you see variables and Quant Comp, make your set-up.

Plugging In is tricky here until you realize that one number must be negative. The 6 in Quantity B is also a clue. Try x = 3 andy = -2. y to the x power will be -8 and x to the y power will be 1/9, so these numbers work. xy = -6 so cross off choices (A) and (C). No matter what you plug in, y must be negative and x must be odd. Therefore xy will always be negative and 6 will always be greater. The answer is choice (B).
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Re: x and y are both integers [#permalink] New post   07 Sep 2023, 00:07
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As Brent explained above x and y are both integers and NEGATIVE.

the OA assumes that x=3 and is not possible. That's why we end up with 1/8 which should be between -1 and 0 and is impossible.

NOT a good question after all
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