Bunuel wrote:
Exactly 8 years ago, Jim’s son was twice as old as Jim’s daughter. If Jim’s son is now 5 years older than his daughter, how old is Jim’s daughter now?
(A) 5
(B) 10
(C) 13
(D) 16
(E) 18
Kudos for correct solution.
Jim’s son is now 5 years older than his daughterLet D = the daughter's age NOW
So D + 5 = the son's age NOW
This also means that
D - 8 = the daughter's age EIGHT YEARS AGO
This also means that D + 5 - 8 = the son's age EIGHT YEARS AGO
Or we can say,
D - 3 = the son's age EIGHT YEARS AGO
8 years ago, Jim’s son was twice as old as Jim’s daughter.8 years ago, the daughter's age was
D - 8 and the son's age was
D - 3So, we can write:
D - 3 = 2(
D - 8)
Expand right side to get: D - 3 = 2D - 16
Solve to get D = 13
Since D = the daughter's present age, the correct answer is C
Cheers,
Brent