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What is (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5)?
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03 Dec 2021, 06:40
03 Dec 2021, 06:40
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Question Stats:
75% (00:39) correct
25% (03:06) wrong based on 8 sessions
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This question is part of the GRE - Skill Builder Project for a Q170
What is \((1 - \frac{1}{2}) + (\frac{1}{2} - \frac{1}{3}) + (\frac{1}{3 }- \frac{1}{4}) + (\frac{1}{4 }- \frac{1}{5})\)?
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4/5
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What is (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5)?
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03 Dec 2021, 06:49
03 Dec 2021, 06:49
1
Carcass wrote:
This question is part of the GRE - Skill Builder Project for a Q170
What is \((1 - \frac{1}{2}) + (\frac{1}{2} - \frac{1}{3}) + (\frac{1}{3 }- \frac{1}{4}) + (\frac{1}{4 }- \frac{1}{5})\)?
Show: ::
4/5
Given: \((1 - \frac{1}{2}) + (\frac{1}{2} - \frac{1}{3}) + (\frac{1}{3 }- \frac{1}{4}) + (\frac{1}{4 }- \frac{1}{5})\)
Remove brackets: \(1 - \frac{1}{2} + \frac{1}{2} - \frac{1}{3} + \frac{1}{3 } - \frac{1}{4} + \frac{1}{4 }- \frac{1}{5}\)
At this point we can see that the six middle fractions all cancel out (e.g., \(- \frac{1}{3} + \frac{1}{3 } = 0\))
So we end up with: \(1 - \frac{1}{5}\), which we can rewrite as \(\frac{5}{5} - \frac{1}{5}\), which evaluates to be \(\frac{4}{5}\)
Answer: \(\frac{4}{5}\)
gmatclubot
What is (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5)? [#permalink]
03 Dec 2021, 06:49
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