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What is the probability that the sum of two rolled dice will
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10 Oct 2017, 20:23
10 Oct 2017, 20:23
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Question Stats:
55% (01:07) correct
45% (01:33) wrong based on 20 sessions
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What is the probability that the sum of two rolled dice will equal a prime number?
(A) 1/3
(B) 5/36
(C) 2/9
(D) 13/36
(E) 5/12
Kudos for correct solution.
(A) 1/3
(B) 5/36
(C) 2/9
(D) 13/36
(E) 5/12
Kudos for correct solution.
Re: What is the probability that the sum of two rolled dice will
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10 Oct 2017, 21:19
10 Oct 2017, 21:19
1
Bunuel wrote:
What is the probability that the sum of two rolled dice will equal a prime number?
(A) 1/3
(B) 5/36
(C) 2/9
(D) 13/36
(E) 5/12
Kudos for correct solution.
(A) 1/3
(B) 5/36
(C) 2/9
(D) 13/36
(E) 5/12
Kudos for correct solution.
Lets find out how many nos. equals to prime number when we add two rolled dice from 1 to 6
So no. of ways are -
1 , 1
1 , 2
2 , 1
1 , 4
4 , 1
1 , 6
6 , 1
2 , 3
3 , 2
2 , 5
5 , 2
3 , 4
4 , 3
6 , 5
5 , 6
Therefore we have 15 possibilities (favourable events)
Total possible events = 6 * 6 = 36 (since one dice contains 6 possible ways)
Therefore
probability = \(\frac{15}{36} = \frac{5}{12}\)
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Re: What is the probability that the sum of two rolled dice will
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15 Oct 2022, 09:55
15 Oct 2022, 09:55
1
Given that two six-sided dice are thrown and we need to find what is the probability that the sum of the numbers showing on the dice is a prime number?
As we are rolling two dice => Number of cases = \(6^2\) = 36
We know that prime numbers are 2, 3, 5, 7, 11 (between 1+1=2 and 6+6 = 12)
Lets start writing the possible cases where sum of the two rolls = 2, 3, 5, 7 , 11. Following are the possible cases:
(1,1), (1,2), (1,4), (1,6)
(2,1), (2,3), (2,5)
(3,2), (3,4)
(4,1), (4,3)
(5,2), (5,6)
(6,1), (6,5)
=> 15 cases
=> Probability that sum of the numbers showing on the dice is a prime number = \(\frac{15}{36}\) = \(\frac{5}{12}\)
So, Answer will be E
Hope it helps!
Watch the following video to learn How to Solve Dice Rolling Probability Problems
As we are rolling two dice => Number of cases = \(6^2\) = 36
We know that prime numbers are 2, 3, 5, 7, 11 (between 1+1=2 and 6+6 = 12)
Lets start writing the possible cases where sum of the two rolls = 2, 3, 5, 7 , 11. Following are the possible cases:
(1,1), (1,2), (1,4), (1,6)
(2,1), (2,3), (2,5)
(3,2), (3,4)
(4,1), (4,3)
(5,2), (5,6)
(6,1), (6,5)
=> 15 cases
=> Probability that sum of the numbers showing on the dice is a prime number = \(\frac{15}{36}\) = \(\frac{5}{12}\)
So, Answer will be E
Hope it helps!
Watch the following video to learn How to Solve Dice Rolling Probability Problems
