We need to find the units digit of \(3^{102}\)Lets start by finding the cyclicity of units' digit in powers of 3
\(3^1\) units’ digit is 3
\(3^2\) units’ digit is 9
\(3^3\) units’ digit is 7
\(3^4\) units’ digit is 1
\(3^5\) units’ digit is 3
That means that units digit of power of 3 has a cycle of 4
=> We need to divide the power (102) by 4 and check what is the remainder
102 divided by 4 gives 0 remainder
=> Units digit of \(3^{102}\) = Units digit of \(3^4\) = 1
So,
Answer will be AHope it helps!
Watch this video to MASTER how to find Units digit of Power of 3