Carcass wrote:
When the positive integer n is divided by 3, the remainder is 2 and when n is divided by 5, the remainder is 1. What is the least possible value of n?
When it comes to remainders, we have a nice rule that says:
If N divided by D leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc. For example, if k divided by 5 leaves a remainder of 1, then the possible values of k are: 1, 1+5, 1+(2)(5), 1+(3)(5), 1+(4)(5), . . . etc.
GIVEN: When the positive integer n is divided by 3, the remainder is 2
The possible values of n are: 2, 5, 8,
11, 14, 17, 20,...
GIVEN: When n is divided by 5, the remainder is 1
The possible values of n are: 1, 6,
11, 16, 21,...
11 is the smallest value that appears in both lists of possible n-values.
Answer: 11
Cheers,
Brent
its easy to understand this rule, just one question, when we should apply this? because questions are really different every time, so how to recognize where this rule will be applicable?
Ever Tried? Ever Failed? No Matter. Try Again. Fail Again. Fail Better!!