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Which is greater \sqrt a+b or \sqrt a + \sqrt b
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28 Dec 2018, 11:27
Expert Reply
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Question Stats:
68% (01:10) correct
31% (00:59) wrong based on 145 sessions
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\(0 < a < b < 1\)
Quantity A
Quantity B
\(\sqrt{a+b}\)
\(\sqrt a + \sqrt b\)
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
Re: Which is greater \sqrt a+b or \sqrt a + \sqrt b
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01 Jan 2019, 08:19
3
Carcass wrote:
\(0 < a < b < 1\)
Quantity A
Quantity B
\(\sqrt{a+b}\)
\(\sqrt a + \sqrt b\)
We know that a and b are POSITIVE
There's a nice rule that says: if 0 < x < y, then 0 < x² < y² In other words, if both quantities are POSITIVE then, if we square both quantities, the comparison remains the same.
So, let's square both quantities to get: QUANTITY A: [√(a + b)]² QUANTITY B: (√a + √b)²
Simplify: QUANTITY A: a + b QUANTITY B: (√a + √b)(√a + √b)
Apply FOIL to Quantity B: QUANTITY A: a + b QUANTITY B: a + √ab + √ab + b
Simplify: QUANTITY A: a + b QUANTITY B: a + 2√ab + b
Subtract a from both quantities: QUANTITY A: b QUANTITY B: 2√ab + b
Subtract b from both quantities: QUANTITY A: 0 QUANTITY B: 2√ab
Since a and b are both POSITIVE, √ab must be POSITIVE, which means 2√ab must be POSITIVE We get: QUANTITY A: 0 QUANTITY B: some POSITIVE number