Carcass wrote:
Which of the following is a possible value of k for which \(\frac{-24}{\sqrt{k}}\) is an integer ?
Indicate all possible choices.
A. 9
B. 12
C. 16
D. 25
E. 64
Let's test each answer choice individually
A. 9. We get: \(\frac{-24}{\sqrt{k}}=\frac{-24}{\sqrt{9}}=\frac{-24}{3}=-8\)
WORKS!!B. 12. We get: \(\frac{-24}{\sqrt{k}}=\frac{-24}{\sqrt{12}}=\frac{-24}{2\sqrt{3}}=\frac{-12}{\sqrt{3}}\)
not an integer C. 16. We get: \(\frac{-24}{\sqrt{k}}=\frac{-24}{\sqrt{16}}=\frac{-24}{4}=-6\)
WORKS!! D. 25. We get: \(\frac{-24}{\sqrt{k}}=\frac{-24}{\sqrt{25}}=\frac{-24}{5}=-4.8\)
not an integer E. 64. We get: \(\frac{-24}{\sqrt{k}}=\frac{-24}{\sqrt{64}}=\frac{-24}{8}=-3\)
WORKS!!Answer: A, C, E
Cheers,
Brent