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x^2 − 11x + |p| = 0, where x is a variable and p is a constant, has 2 : Quantitative Comparison Questions

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Re: x^2 11x + |p| = 0, where x is a variable and p is a constant, has 2 [#permalink]
AnkitaShinde wrote:
Is there some other solution?


There are several more solutions to this question on GMAT Club (GRE Prep Club's sister site): https://gmatclub.com/forum/if-x-2-11x-p ... 25456.html
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Re: x^2 11x + |p| = 0, where x is a variable and p is a constant, has 2 [#permalink]
1
This is my own solution


For the equation to have 2 distinct roots there are two cases

Case 1


If p is positive


b^2-4ac>0

121-4p>0

-4p>-121

p<121/4

Case 2

Where p is negative


121+4p>0

4p>-121

p>-121/4


Combining both inequalities we have

-121/4<p<121/4

-30.25<p<30.25


Integer values will then be

-30<=p<=30



Of these p can take integers -30, -28, -24, -18, -10, 0, 10, 18, 24, 28, 30.

Quantity A is greater

Motion2020 made a mistake with -8 and 8, 10 and -10 will go instead. Hope it helps.

Adewale Fasipe, GRE/GMAT quant instructor from Nigeria. You may contact me for classes here.
https://www.teacheron.com/tutor-profile/8tG7?r=8tG7
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Re: x^2 11x + |p| = 0, where x is a variable and p is a constant, has 2 [#permalink]
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