Carcass wrote:
x and y are positive integers such that \(x^25^y = 10,125\)
Quantity A |
Quantity B |
\(x^2\) |
\(5^y\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
This question begs for some
prime factorization10,125 = (5)(5)(5)(3)(3)(3)(3)
From this, we can see a few options for x² and 5^y
Here are two possible cases:
case 1: x = 45 and y = 1.
So, (x²)(5^y) = (45²)(5^1)
= [(3)(3)(5)]²(5)
= (3)(3)(3)(3)(5)(5)(5)
= 10,125
For this case, we get:
Quantity A: 45²
Quantity B: 5
Quantity A is clearly greater
case 2: x = 9 and y = 3.
So, (x²)(5^y) = (9²)(5^3)
= [(3)(3)]²(5)(5)(5)
= (3)(3)(3)(3)(5)(5)(5)
= 10,125
For this case, we get:
Quantity A: 81
Quantity B: 125
Quantity B is clearly greater
Answer:
Cheers,
Brent