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Re: x is an integer. If [m]x>9[/m], and [m]x^3+3x^2+2x[/m] is no [#permalink]
2
I have a slightly different way of solving the question.

I started by plugging in possible numbers for x in x^3+3x^2+2x. I started with 10 and 11, found out that the answers are divisible by 4, then tried 17 which intuitively felt like there is a higher possibility of it not being able to be divided by 4.
Indeed, 17^3+3(17)^2+2(17)= 5814, which is not divisible by 4.

I then looked at the answer options for the next step- since the answer options are of numbers which are smaller than x, I had to think of a number that is smaller than 17 and is a multiple of 4. 12 is smaller than 17 and is divisible by 4 and 17-12=5
Therefore, x-5 MUST be divisible by 4 and (C) is the correct answer.
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Re: x is an integer. If [m]x>9[/m], and [m]x^3+3x^2+2x[/m] is no [#permalink]
gwent wrote:
I have a slightly different way of solving the question.

I started by plugging in possible numbers for x in x^3+3x^2+2x. I started with 10 and 11, found out that the answers are divisible by 4, then tried 17 which intuitively felt like there is a higher possibility of it not being able to be divided by 4.
Indeed, 17^3+3(17)^2+2(17)= 5814, which is not divisible by 4.

I then looked at the answer options for the next step- since the answer options are of numbers which are smaller than x, I had to think of a number that is smaller than 17 and is a multiple of 4. 12 is smaller than 17 and is divisible by 4 and 17-12=5
Therefore, x-5 MUST be divisible by 4 and (C) is the correct answer.


Great reasoning!

Cheers,
Brent
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