Farina wrote:
I solved it by drawing perpendicular in between and it became 30-60-90 triangle.
x : x* sqrt3: 2x
we know that x=2
if i compare 2x=2, i get x=1 and I get correct answer of area of triangle
if i compare x* sqrt3 = 2, i get x=2/sqrt3, which is incorrect
Can anyone tell me, do we always have to compare value of any side with hypotenuse? i.e. 2x here
Relation between angle and side length is always fixed ie. 30-60-90 has the ratio of the side as x : \(\sqrt{3}\) * x: 2x
That also means, opposite to 30 the side length is x;
Opposite to 60 side length is \(\sqrt{3}\) * x
And opposite to 90, it is 2x
This is always fixed!